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OpenStudy (anonymous):
be rational! ;)
OpenStudy (anonymous):
The celestial sphere shown at right has radius
9 inches. The planet in the sphere’s center
has radius 3 inches. What is the ratio of the
volume of the planet to the volume of the
celestial sphere? What is the ratio of the
surface area of the planet to the surface area
of the celestial sphere?
OpenStudy (anonymous):
So you'll need to put the surface area of the one, over the other, and same for volume. I'm assuming you have/know the formula for the surface area or volume of a sphere..
OpenStudy (anonymous):
you mean 4/3pi3 right
OpenStudy (anonymous):
\[V = \frac{4}{3}\pi r^3\]
\[A = 4\pi r^2\]
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OpenStudy (anonymous):
So the ratios will be
\[\frac{V_3}{V_9} \text{ and } \frac{A_3}{A_9}\]
OpenStudy (anonymous):
for 9 is 972pi and 324pi and for 3 36pi and 36pi
OpenStudy (anonymous):
You need to divide them
OpenStudy (anonymous):
show me how..
OpenStudy (anonymous):
\[Ratio_{volume} = \frac{324\pi}{972\pi}\]
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OpenStudy (anonymous):
i got 0.33333333333
OpenStudy (anonymous):
Hrm.. I think your original numbers are problematic...
You should have..
\[\frac{\frac{4}{3}\pi 3^3}{\frac{4}{3}\pi 9^3} = \frac{3^3}{(3^2)^3} = \frac{3^3}{3^6} = \frac{1}{3^3} = \frac{1}{27}\]
OpenStudy (anonymous):
so that mean 1:3
OpenStudy (anonymous):
no that means 1:27
OpenStudy (anonymous):
for volume or SA
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