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Mathematics 14 Online
OpenStudy (anonymous):

can somebody help me with ration please

OpenStudy (anonymous):

be rational! ;)

OpenStudy (anonymous):

The celestial sphere shown at right has radius 9 inches. The planet in the sphere’s center has radius 3 inches. What is the ratio of the volume of the planet to the volume of the celestial sphere? What is the ratio of the surface area of the planet to the surface area of the celestial sphere?

OpenStudy (anonymous):

So you'll need to put the surface area of the one, over the other, and same for volume. I'm assuming you have/know the formula for the surface area or volume of a sphere..

OpenStudy (anonymous):

you mean 4/3pi3 right

OpenStudy (anonymous):

\[V = \frac{4}{3}\pi r^3\] \[A = 4\pi r^2\]

OpenStudy (anonymous):

So the ratios will be \[\frac{V_3}{V_9} \text{ and } \frac{A_3}{A_9}\]

OpenStudy (anonymous):

for 9 is 972pi and 324pi and for 3 36pi and 36pi

OpenStudy (anonymous):

You need to divide them

OpenStudy (anonymous):

show me how..

OpenStudy (anonymous):

\[Ratio_{volume} = \frac{324\pi}{972\pi}\]

OpenStudy (anonymous):

i got 0.33333333333

OpenStudy (anonymous):

Hrm.. I think your original numbers are problematic... You should have.. \[\frac{\frac{4}{3}\pi 3^3}{\frac{4}{3}\pi 9^3} = \frac{3^3}{(3^2)^3} = \frac{3^3}{3^6} = \frac{1}{3^3} = \frac{1}{27}\]

OpenStudy (anonymous):

so that mean 1:3

OpenStudy (anonymous):

no that means 1:27

OpenStudy (anonymous):

for volume or SA

OpenStudy (anonymous):

that was for volume

OpenStudy (anonymous):

but now i need ratio for SA

OpenStudy (anonymous):

so do the same thing

OpenStudy (anonymous):

but with the surface area formula

OpenStudy (anonymous):

324 and 36

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