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Find the vertices of the hyperbola with equation: (x+2)^2/4 - (y+1)^2/16. very last question!
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yay!! the vertices are along the + variable; and that is.....x axis
the major line is centered at (-2,-1) so the verticeses are (+-x, -1)
make y=0 to find x :)
x+2 = +-2 x = 0 and -4
(0,-1) and (-4,-1)
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im pretty sure thats it
ok that is what I got too so i think that it is correct :)
-2+2 = 0 -2-2 = -4; its good :)
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