Question

f(x)=x sin x(x^2) Find f^(2011) (0).

Answer 1

2011/360=?

Answer 2

5.58611 degrees; but is 2011 in radians or degrees for that?

Answer 3

I believe you have to work this using Taylor series

Answer 4

oh.... then you prolly want someone else to help you ; like the cow :)

Answer 5

rude.

Answer 6

no..... rude would be me doing something absurd and uncalled for; this is just me not being good with taylor series and suggesting you find someone smarter than me...

Answer 7

like...the cow here :)

Answer 8

oh ok ok
i mis understood u then . thanks for attempting

Answer 9

sorry i couldnt help out :) good luck with it tho ;)

Answer 10

Just for clarification, is it \[x \sin (x*x ^{2})\]

Answer 11

no its (x)(sin(x^2)

Answer 12

)

Answer 13

so if you taylor expand this, you will get\[x(x^2 - (x^2)^3/3! - (x^2)^5/5! + ...)\]

Answer 14

and if you plug in 0 for this you get 0 .-.

Answer 15

did u use a formula

Answer 16

well, I just used the taylor expansion of sin x
and then I plugged in x^2 for that x

Answer 17

then multiplied the series by x right??

Answer 18

yup!

Answer 19

and because you can always factor out an x term, when you plug in x, you'll get 0, or at least this is my idea of how it works

Answer 20

"no its (x)(sin(x^2)"
f(x)= x*sin(x^2)
f(0) = 0. At the origin both x x^2 are zero. Thus the product of x and Sin[x^2] is zero.
Refer to the attached plot, Nora_1.pdf .

Answer 21

Robtobey, I think the problem isn't taking the function to the 2011 power, but rather taking the 2011 derivative