Add. Simplify by removing factors of 1
28zx + z-7x
----- -----
z^2-49x^2 z+7x

Question

Add. Simplify by removing factors of 1
28zx      +            z-7x
-----                   -----
z^2-49x^2           z+7x

anonymous · Answer

What? :)

anonymous · Answer

Add. simplify by removing factors of 1

anonymous · Answer

step by step so i can make notes to do next one on my own plz

myininaya · Answer

$$\frac{28zx}{(z-7x)(z+7x)}+\frac{z-7x}{z+7x}$$

myininaya · Answer

i have to go but u need to find a common denominator

anonymous · Answer

i really need help someone plz

anonymous · Answer

i really need help someone plz

anonymous · Answer

Okay, I see the exercise in mathematical notation now, so I know what to do. :) Here is how it goes...

1) 28zx/(z-7x)(z+7x) (explanation: 28zx remains as is for now, but we have to focus on this part (z-7x)(z+7x) so follow up close with what I'm doing here: the first part (z - 7x)...z and -7x multiplies with the first and second of the second parenthesis like so: (z-7x)(z+7x) = z^2 + 7zx - 7zx - 49x^2 and now you keep solving z^2 - 49x^2, and now you have 28zx/z^2-49x^2 + z-7x/z+7x and now you kind of have to apply what you learned about adding fractions...)

You multiply them in cross... 28zx * z + 7x and z^2 - 49x^2... and see what you get.

anonymous · Answer

@tina-ann: Did I help any? :-)

anonymous · Answer

yes but could you show ur work

anonymous · Answer

Please forget everything I wrote earlier. :-)

I'm not so sure at the moment how I can do it, but I'll post as soon as I get it solved.