Question

how to determine if a given number is a perfect square or not?

Answer 1

Find the square root, and see if its an integer or not. If its an integer then the number was a perfect sqare

Answer 2

any other short cuts?

Answer 3

Depends on the case you are dealing with

Answer 4

any example?

Answer 5

You give me examples and I will do it for you, I don't know your level. If I say
If 8n+1 is a perfect square what can you say about n
then this question can go above your level. So you need to tell me what you r level is

Answer 6

1,3,6,10,15,21,28,36,45 and so on. couldn't reply yesterday b coz of connection failure

Answer 7

ha ha. No not that. The answer is "2n can't be a perfect square" or
"\[\sqrt (8n+1)\]" is always odd.

Answer 8

i don't get u

Answer 9

Thats why I told you to provide me problems, rather than having problems from me.

Answer 10

8(1)+1=9
8(3)+1=25
8(6)+1=49
8(10)+1=81
all of them are perfect squares. what then?

Answer 11

The question was, what is the property of n, when 8n+1 is a perfect square. What you are doing is just putting values and seeing if they are satisfying the relation I gave you. But thats not the problem. The problem is to prove the two answer statement I gave you. i.e. "2n can't be a perfect square" or "(√8n+1) is always odd."
I didn't get them by guess work, I proved them, and that is what is expected.

Answer 12

oh ok. thanks

Answer 13

thanks again then:)