Question

Simplify: Radical 16r ^7 s^5+ 7r^2 Radical r^3s^5-7rs radical r^5s^3

Answer 1

ok

Answer 2

\[\sqrt{16r^7s^5}+7r^2\sqrt{r^3 s^5}-7rs \sqrt{r^5s^3}\]
you mean this?

Answer 3

im guessing each are different?

Answer 4

need clarification

Answer 5

yes i meant that \. I didn't know how to to type it

Answer 6

o.k, so first look at the radical sign

Answer 7

you want to grab pairs

Answer 8

so you can rewrite it as \[\sqrt{16r^6rs^4s}\]

Answer 9

for the first term

Answer 10

so just take each individual root

Answer 11

\[\sqrt{16}=4\]

Answer 12

one way to look at the r^6 is to divide the exponent by 2

Answer 13

you will do the same to the s^4

Answer 14

Ive done all of this correct, but i keep getting the wrong answer

Answer 15

we need pairs so we will have r and s inside the radical.

Answer 16

o.k, what are u getting?

Answer 17

What did you get?

Answer 18

???

Answer 19

what is you final answer?

Answer 20

im getting \[4r^3s^2\sqrt{rs}\]