Question

For any positive rational number k, and any real number c, which of the following is incorrect? a.limxaprochinf c = c b limitxaproch-inf. c = c c.limitxaprochinf c/x^k = 0
d.limitxaproch-inf c/x^k = 0 e. All are correct

Answer 1

see i already answered this
lol

Answer 2

D!

Answer 3

no D is true
its e

Answer 4

sory i have corrected choice d can u see it plzzzz?

Answer 5

yes i see it
e is the answer
they are all true

Answer 6

plz can u explain it?

Answer 7

c in constant it has one value no matter what x is its a horizontal line
so didn't doesn't matter what x approaches f(x) will always appoach c since f(x)=c.
now what 1/x approach if x approaches infinity?

Answer 8

Wait, I still think d is false. Think about it, as the denominator goes to -infinity, wouldn't it go to 0.
Now 1/0 = infinity

Answer 9

oh k is rational not an integer so that means if we have 1/(x^(1/2)), then x-> -inf,
f wouldn't exist.
if k is integer d is true

Answer 10

no phinx it will go to 0 if the funtion exist for negative numbers

Answer 11

ohhh, I misread

Answer 12

but still d is not true since k is rational

Answer 13

can u plz solve it by steps?

Answer 14

1 / infinity = 0

Answer 15

It has to be d)

Because, the limit does not exist, x^k does not exist for negative numbers, if k is any rational number