Question

A sphere of mass 50gm and radius 10cm rolls without slipping with a velocity of 5cm/s.
Its total kinetic energy in ergs is?

Answer 1

KE = translational KE + rotational KE. So translational KE is 1/2mv^2. Rotational KE is 1/2Iw^2. I is the moment of inertia for a solid sphere.

Answer 2

I think it may need a bit more...maybe not but oh well

there are some ideas missing here...the moment of inertia of a sphere is I=mr^2

and the angular velocity is going to be the 5cm/s divided by the radius.
Those are going to be need to calculate better...I hope I wasnt going too deep

http://mathphystut.tripod.com

Answer 3

the moment of inertia of a sphere is I=2/5mr^2
you might wanna check that

Answer 4

ooo...nice call...you a head cracker deeprony

Answer 5

thanx for the heads up...i dont know how I messed that one up

Answer 6

no worries. happens to the best of all...=)

Answer 7

hey can you help me with this one,
If (2,-8) is the coordinates of an end point of a focal chord of y^2=4ax, then the co-ordinates of the other end are?