Question

hey, sorry about going off subject, i would like to ask a question on physics. Since there isn't anyone in that section i am helpless.
here is my question: A cylinder of radius 20cm and mass 100g rolls down an inclined plane of height 60cm without slipping. the linear velocity of the cylinder at the bottom is?? (g=980cm/s/s)

Answer 1

mgh = KE

Answer 2

1/2 mv^2+1/2 I w^2= Mgh

Answer 3

i did that but i m not gettin the answer.

Answer 4

KE = KE(r) + KE(t)
1/2(mr^2/2)w^2 + 1/2 x m x v^2

Answer 5

rw=v
w=v/r
substitute

Answer 6

3/4 x mv^2 = mgh

Answer 7

i went through all that buddy. can you solve ang post your anser.

Answer 8

*and
*answer

Answer 9

v=2.8 m/s

Answer 10

ow rats! i made a calculation mistake! neway thnx buddy..

Answer 11

no prob

Answer 12

wat is the radius of curveture if a particle moves in a trajectory given by y=f(x) at any point(x,y)

Answer 13

parameterize the eqn in terms of time....r =v^2/a(radial)

Answer 14

it is given as \[R=[1+(dy/dx)^{2}\left[ \right]^{3/2}\]

Answer 15

divied by d^2y\dx^2

Answer 16

if u know the answer then y do u ask..i dont memorize formulae..its wiser to go through the basic approach...

Answer 17

i want to kno how it came