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Solve this differential equation by eliminating the arbitrary constants. y=Acos(log x) + Bsin(log x)
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the equation or differential equation?
diffrential eqn
but where are the differentials?
you have to eliminate A & B
i guess this is the prob to form a DE
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Yea DE.
question makes no sense
eq contains 2 constants, differentiate twice n solve
how this makes no sense? this is que from book. @ elecengineer
Yea But M unable to solve.can u help me in differentiating?
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y'=-Asin(logx)(1/x)+Bcos(logx)(1/x) y''=-Acos(logx)(-1/x^2)-Bsin(logx)(-1/x^2) =(1/x^2)[Acos(logx)+Bsin(logx)] y''=(1/x^2)y
okay thank u so much uzma let me check
what :|
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