if $300 is deposited in an account and it increases to $450 in eight years compounded quarterly. find the rate of interest to the nearest tenth
450 = 300(1+ r/4)^(8r)
and how do i solve that @amistre64
with cunning and style
46.28%
divide 300 take logs; and use rules of logs to manipulate it
or graph it and find the zero
thank you
can you show me step by step
i can try lol
ok thanks lol
@ amistr64 can i ask you a question when you done helping them
its easier on paper... 450/300= 3/2 3/2 = (1 + r/4)^(8r) log(3/2) = log(1+ r/4)^(8r) log(n) = 8r log(1+ r/4) log(n) ---------- = 8r log(1 + r/4)
so problems like this have to be solved with a calculator?
log(3) - log(2) -------------- = 8r log(4+r) - log(4) A ---------- = 8r log(4+r) - B log(4+r) - B = A/8r etc...
it canbe done by hand, but its alot of window dressing to get it to the right spot
and the way you doing it here is by hand or calculator
@amistre are you still there
by hand; which is why i left it alone really; :)
oh ok
Join our real-time social learning platform and learn together with your friends!