Definite integral this time:
from [1,-2]
1-2x+3d^2 dx
Integral I get is: x-x^2+x^3
Evaluate at 1 for ... 1
Evaluate at -2 for ....-14
1-(-14)=1+14=15.....oh that is the right answer...dang double negatives....nevermind

bonus question though...why isnt the equation editor thing available for the question or is it but I don't know how to access it?

Question

Definite integral this time:
from [1,-2]
1-2x+3d^2 dx
Integral I get is: x-x^2+x^3
Evaluate at 1 for ... 1
Evaluate at -2 for ....-14
1-(-14)=1+14=15.....oh that is the right answer...dang double negatives....nevermind

bonus question though...why isnt the equation editor thing available for the question or is it but I don't know how to access it?

amistre64 · Answer

3d^2 ?

amistre64 · Answer

double integral right?

amistre64 · Answer

gotta type like this '\' [\stuff in here\], without the '' parts:

$$\sin(32)^2 + \frac{x}{x} - int_{1}^{4}(x)dx$$

amistre64 · Answer

gotta put some spurious \\ s in it lol

anonymous · Answer

Okies I'll try putting in some slashies when my final isnt tomorrow =)