Question

PLEASE HELP
Write cos(t) in terms of csc(t) if the terminal point determined by t is in quadrant II.

Answer 1

csc is in inverted sin; and cos is a shifted sin...

Answer 2

cos(t) = sin(t+ (pi/2))

csc(t) = 1/sin(t)

sooooo.....

cos(t) = 1/csc(t+ (pi/2))

Answer 3

My only options are
A. -((csc t)/(sqrt 1 + csc^2t))
B. -((1)/(sqrt 1 + csc^2t))
C. - ((sqrt csc^2t -1)/(csc t))
D. ((1)/(sqrt csc^2t -1))
E. -((1- csc^2t)/(csc t))

Answer 4

csc is negative in q2; so d is out

Answer 5

we can work it backwards as well; pick an angle you know the cos and csc to in Q2 and we what fits :)

Answer 6

cos(120) = 1/2 ; the sin(120) = -sqrt(3)/2; csc(120) = -2/sqrt(3)

Answer 7

-2 1
--------*k = ---
sqrt(3) 2


sqrt(3)
k = - --------
4

Answer 8

i cant get a clear picture in my head of what the problem is asking for yet....

Answer 9

csc(t) = 1/sin(t)
\[cos(t) = \sqrt{1-\sin^2t}\]
\[\cos(t) = \sqrt{1-1/\csc^2t}\]

Answer 10

It is in the II quadrant, so C is the option!