Question

How many different three-letter arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?

A. 56
B. 112
C. 168
D. 336

Answer 1

Woo!! last question!! ^^

Answer 2

There are 8 letters and we want to choose 3 among them. So 8 choose 3, i.e
\(\frac{8!}{5!3!}=\frac{6\times 7\times 8}{1\times 2\times 3}=56\)

Answer 3

simplify the expression:
(√7+√385)(√55+√11)

Answer 4

Ohhhh okie dokie (: Thanks a but load