Question

Solve:
sec²θ = 2tanθ+4 over the interval [0,2pi)

Answer 1

\[\sec ^{2}\theta=1+ \tan ^{2}\theta\]
\[\tan ^{2}\theta - 2\tan \theta - 3=0\]
solve quadratic equation for tan:
you'll have:
\[\tan \Theta=-1 and \tan \theta=3\]
what is the value of theta it corresponds...?
find it :)

Answer 2

I did get that far, but don't know how to figure what it corresponds to