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Mathematics 12 Online
OpenStudy (anonymous):

Consider the linear transformation T: C^2-> C^2 given by T(z,w,)=(2z,z+w). Find the eigenvalues and eigenvectors for T.

OpenStudy (nowhereman):

Look at the characteristic polynomial to find the eigenvalues. Then solve for each ev λ the linear equation Tx = λx.

OpenStudy (anonymous):

Well in this case the matrix is \[(2 & 0 \ 1 & 1)\]. So the characterestic poly is \[(2-\lambda)(1-\lambda) = 0\]. You wil get \[2\lambda^ 2 \]. Solve for \[\lambda\] to get the eigenvalues.

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