Question

\[p = \sqrt{2 - p}\]

Answer 1

could you better yet show me how to do them?

Answer 2

p=sqrt(2-p)
First, square both sides.
p²=2-p
Then, throw everything to one side.
p²+p-2=0
Then, factor it.
(p+2)(p-1)=0
p+2=0 or p-1=0
p=-2 or p=1

Answer 3

this goes against every rule in algebra so far. my teacher gave every one F's because he thinks we cant learn -_-

Answer 4

sqrt(4) does not equal -2

Answer 5

I wasn't done yet.

Answer 6

1 is good

Answer 7

waiit so what is the other one?

Answer 8

2

Answer 9

p=-2 is wrong, since sqrt(2-p) can't become lower than 2.

Answer 10

only 1; when squareing sides, you run the risk of getting a false answer and have to check it back into the original to see if it works :)

Answer 11

so then it is any number greater than 2?

Answer 12

sqrt(2-p) shouldnt go below zero; below 2 is fine :)

Answer 13

sqrt(2--2) = sqrt(4) = 2

-2 <> 2

Answer 14

ok... this is confusing

Answer 15

what is confusing about it?

Answer 16

just the way my teacher told us only to do it a way i dont remember and like coding learn 2 at once you get raped... :/

Answer 17

there are only two numbers whose value equals their sqrts; do you know those numbers?

Answer 18

for this one?

Answer 19

for any number....

does 0 = sqrt(0) ??

does 1 = sqrt(1) ??

Answer 20

no sqrt for 1

0 = \[\sqrt{0}\]

Answer 21

1*1 = 1 ; therefore; sqrt(1) = 1 right?

Answer 22

wouldnt it equal \[\sqrt{1}\]

Answer 23

1 = 1*1 = sqrt(1) = 1/1 = .....

Answer 24

p = sqrt(2-p) what should we do to solve this?

Answer 25

i dont even know. :/

Answer 26

staring at it wont help :)

Try something, even if its wrong....

Answer 27

give me a minute...

Answer 28

\[-2^{?} +p ^{?}\]

Answer 29

ohh the question marks should be sqrd

Answer 30

its a good attempt; but how do we 'do the same thing' to the other side of the equals?

Answer 31

how do we 'undo' a square root?

Answer 32

square it

Answer 33

yes; so lets try that :) to both sides

Answer 34

p^2 = sqrt(2-p)^2

p^2 = 2-p

Answer 35

4 + psqrd = 0?

Answer 36

do you see that steps I did?

Answer 37

yes

Answer 38

when you square the squarroot; sign; it disappears; that is the only thing that happens to that part....

Answer 39

ok

Answer 40

sqrt(15)^2 = 15

sqrt(3)^2 = 3

sqrt(23654)^2 = 23654

see it?

Answer 41

sqrt(2-p)^2 = 2-p right?

Answer 42

yeah

Answer 43

p^2 = 2-p ; what do you wanna do to this to solve for p?

Answer 44

same side?

Answer 45

ok...lets put it all to the same side....

p^2 +p -2 = 2-2-p+p

p^2 +p -2 = 0

Answer 46

ok

Answer 47

how do we 'unFOIL' this ?

Answer 48

huhm flutter if i know.

Answer 49

please dont use that language here

Answer 50

kk

Answer 51

i never understood the foil. my teacher writes it on the bored and says his thought erases then goes to the next prob

Answer 52

FOIL is a term that is used to teach people how to multiply stuff inside of paranthesis

Answer 53

ok

Answer 54

they teach it in hopes that it will mean something later on; but really its a crutch that keeps you from learning whats really happening to a problem

Answer 55

The distributive property is all that we need; do you remember the distributive property?

Answer 56

i ask for help bet he says a smart alic reply to me... he needs a different career

Answer 57

yeah

Answer 58

How do we use the distributive property then?

Answer 59

times outside the ( ) by the inside of the ( )

Answer 60

very good :)

We can do that as many times as it takes.... watch:

Do you agree that 8*3 = 24?

Answer 61

yep

Answer 62

then 3(5+3) should also equal 24 right?

3(5) + 3(3) = 24

15 + 9 = 24

24 = 24

Answer 63

ok

Answer 64

and... (1+2)(5+3) should also equal 24..like this:

(1+2)(5) + (1+2)(3) = 24

5(1) + 5(2) + 3(1) + 3(2) = 24

5 + 10 + 3 + 6 = 24

15 + 9 = 24

24 = 24

that is what they are calling FOIL..... its just using the distributive property twice

Answer 65

ok
so foil = complete distribution?

Answer 66

yes :)

Answer 67

ok.. u got a mic or something for pc? this would be easier...

Answer 68

nope; using college computers..no sound no video no nothing but a keyboard

Answer 69

darn... ok so please guide me through the problem im about to make a new post... itl be easier...

Answer 70

ok...

Answer 71

i posted it...