Question

\[x = \sqrt{8x}\]

Answer 1

this one right?

Answer 2

yup

Answer 3

the answer should be 0 :) but lets see if we can get to that

Answer 4

kk

Answer 5

we know to square it to get rid of the squareroot right?

Answer 6

yeah

Answer 7

\[x^2 = \sqrt{8x}^2\]
\[x^2 = 8x\]

Answer 8

so 16 + 2sgr = o

Answer 9

we move it all to one side now right?

Answer 10

yes.. was mine right?

Answer 11

\[x^2 -8x = 8x -8x\]
\[x^2-8x = 0\]

Answer 12

ohh

Answer 13

16 + 2sqr....no

Answer 14

i hate math D:

Answer 15

:) itll get easier

Answer 16

We can factor out an 'x' from our equation now right?

Answer 17

yeah now that imma have to repeat algebra 1 :(

Answer 18

yes

Answer 19

\[x(x-8) =0\]

Answer 20

xsqr - 8x = 0

Answer 21

now the key to solve this is to know that anything times 0 equals 0 right?

so we have 2 options...

if x = 0 then; (0)(0-8) = 0

and

if x = 8 then; (8)(8-8) = (8)(0) = 8


So we have to test for x = 0 and x = 8 in the original problem to see if these are good....

Answer 22

so x=0 or x=8

Answer 23

\[0=\sqrt{8*0}\] thats true

\[8 = \sqrt{8*8} = \sqrt{64}\]and thats tru; so yes
x = 0 or 8

Answer 24

ok

Answer 25

x=\[\sqrt{42-x}\]

Answer 26

gonna have to post that for someone else to help with; i gotta get to class :)

Answer 27

thanks

Answer 28

\[\sqrt{8 x}=2 \sqrt{2} \sqrt{x} \]\[x=2 \sqrt{2} \sqrt{x} \]x = 0 or 8