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"The perimeter of a rectangle is 18 inches. The length is three more than the width. What is the length?" So far I've got: P=18 L+3=W And so I think [(L+3)+w]2=P But I could be wrong...Any takers?
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P = 2(L+W)
If you want just one variable (and I think you do) w = L+w means that L = w-3 using daniel's equation P=2((w-3)+w) ya? or 18=2w-6 and then it is easy
2(l+w) = 18 2(w+3+w)=18 since l is w+3 substitute .. 2w+3=9 w=3
aaak that should be w = L +3 but you knew that
w=3 so l is 6
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hi cna u help me after her
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