The center of a circle is the point C(2,4), and P(-1,6) is a point on the circle. Find the equation of the line tangent to the circle at the point P.

Question

anonymous · Answer

Already answered: distance = sqrt (13)
Answer:
$$(x-2)^2 + (y-4)^2 = 13$$

anonymous · Answer

i think this question asks for tangent line yes?  not equation of the circle.  need calc.

anonymous · Answer

Lol.  I fail.  Answer will be up in a second. FORGIVE ME :D

anonymous · Answer

slope for CP = 6-4/ -1-2 = -2/3
slope for line (perpendicular to CP) = 3/2
y = mx +b  m = 3/2
6 = -3/2 + b;  b = 15/2
y = 3x/2 +15/2

anonymous · Answer

oops i fail too!  i thought i would have to use implicit diff!  F for me.

anonymous · Answer

Lol.  Implicit diff would have been hard and it wouldn't have worked :D