Question

3=(3x^2y^0z^-4)^-3 I cant have any Zero, negative or fraction exponents.

Answer 1

you do not mean 3= do you?

Answer 2

Yeah ignore that

Answer 3

Typo

Answer 4

\[(3x^2y^0z^{-4})^{-3}\]

Answer 5

Thats exacty how i have it

Answer 6

multiply all the exponents by -3, ignore the \[y^0\] because it is 1

Answer 7

\[3^{-3}x^{-6}z^{12}\] ones with negative exponents go down, rest stays up.
\[\frac{z^{12}}{3^3x^6}\]

Answer 8

trick is to not forget the 3. it gets raised to the -3 as well.

Answer 9

Basic multiplication rules apply? two negatives = posative, + and - = negative?

Answer 10

*when multiplying exponents

Answer 11

of course. all normal rules of arithmetic work even when working with exponents.

Answer 12

One problem
I think you did it wrong

Answer 13

Wait, im confused. How did oyu get 3^-3

Answer 14

aha i knew it. you have to raise EVERYTHING to the power of -3 because everything was in the parentheses

Answer 15

Ahah!

Answer 16

example \[(2x^3y^{-2})^{-2}\]
\[=2^{-2}x^{-6}y^4\]
dont forget the 2!

Answer 17

What about X^3 times X^-5

Answer 18

is it X^-15?

Answer 19

or X^2

Answer 20

*X^-2

Answer 21

\[x^3x^{-5}=x^{3-5}=x^{-2}=\frac{1}{x^2}\]

Answer 22

dont forget
\[x^{-5} = \frac{1}{x^5}\] so \[x^3x^{-5}=\frac{x^3}{x^5}=\frac{1}{x^2}\]\]

Answer 23

in other words it makes sense to add the exponents when you multiply whether they are positive or negative.

Answer 24

Only multiply when its an exponent to another power right?

Answer 25

yup

Answer 26

\[b^n b^m = b^{n+m}\]
\[(b^n)^m=b^{mn}\]

Answer 27

(-4xy^-5)/(24x^-3) How do i take the recripical of this one?

Answer 28

\[\frac{-4xy^{-5}}{24x^{-3}}\]

Answer 29

Correct

Answer 30

if the exponent is negative move it from down to up or from up to down. do not mess with the coefficients. they have no exponents attached.

Answer 31

\[\frac{-4xx^3}{24y^5}\]

Answer 32

now all the exponents are positive. of course you can simplify this:
\[-\frac{x^4}{6y^5}\]

Answer 33

thanks dude