derive this! dB/dt= k 100A/rW e^-kt - V

Question

derive this!  dB/dt= k 100A/rW e^-kt - V

anonymous · Answer

im pretty sure its -kte^-kt

anonymous · Answer

how many variables are there? k,A,r,W and V are constants?

anonymous · Answer

yeah they're constant, so i thought i could just eliminate

dumbcow · Answer

is e^-kt in denominator ?

anonymous · Answer

dB/dt is B'(t)
so do you want B"(t)?

anonymous · Answer

http://www.wolframalpha.com/input/?i=What%20would%20you%20like%20to%20know%20about%3Fderive%20this!%20%20dB%2Fdt%3D%20k%20100A%2FrW%20e^-kt%20-%20V

dumbcow · Answer

-k^2(100A/rW)e^-kt

anonymous · Answer

if k,A,r,W and V are constants and if you are looking for B"(t) then, k100A/rW still stay where is, e^-kt would be -k e^-kt, (t is a variable), and V will just disappear.

so your answer would be $$d ^{2}B/d t^{2}=-(k ^{2}100/rW) e ^{-kt}$$

anonymous · Answer

I forgot the A after the 100 of course, haha...

more calculus and DE problems here would be nice...

anonymous · Answer

ill put some more up then, thanks guys

anonymous · Answer

hm, maybe tomorrrowws