Graph the feasible region to the following system of inequalities
y-2x≥1
2x+3y≥6

Question

amistre64 · Answer

with what?

anonymous · Answer

or how would you go about solving it?

anonymous · Answer

draw the two lines, the feasible region lies above both of the lines

amistre64 · Answer

graph the lines:

y-2x = 1

and  2x +3y = 6

amistre64 · Answer

then determine which point, not on the line; satisfies the equatons

anonymous · Answer

if the inequalities were less than or equal to would i shade below the lines?

amistre64 · Answer

pick (x=0,y=0) since its not on the line.... if it makes a true statement, sahde that side; if false? shaded the other side

anonymous · Answer

feasible region can be found by putting (0,0) in the line,

anonymous · Answer

yes amistre is right

anonymous · Answer

origin is easiest point to check for the required region

amistre64 · Answer

by true statement i mean, use it in the original inequality :)

anonymous · Answer

$$y-2x \ge 1$$

anonymous · Answer

substituting x=0 and y=0
o greater than /equal 1,false

anonymous · Answer

so the area opposite to origin is shaded

anonymous · Answer

similar for the second line
if the two region coincide, it is the required region, otherwise solution does not exist