Question

Graph the feasible region to the following system of inequalities
y-2x≥1
2x+3y≥6

Answer 1

with what?

Answer 2

or how would you go about solving it?

Answer 3

draw the two lines, the feasible region lies above both of the lines

Answer 4

graph the lines:

y-2x = 1

and 2x +3y = 6

Answer 5

then determine which point, not on the line; satisfies the equatons

Answer 6

if the inequalities were less than or equal to would i shade below the lines?

Answer 7

pick (x=0,y=0) since its not on the line.... if it makes a true statement, sahde that side; if false? shaded the other side

Answer 8

feasible region can be found by putting (0,0) in the line,

Answer 9

yes amistre is right

Answer 10

origin is easiest point to check for the required region

Answer 11

by true statement i mean, use it in the original inequality :)

Answer 12

\[y-2x \ge 1\]

Answer 13

substituting x=0 and y=0
o greater than /equal 1,false

Answer 14

so the area opposite to origin is shaded

Answer 15

similar for the second line
if the two region coincide, it is the required region, otherwise solution does not exist