Question

how do you integrate t times e to the negative t? (te^-t)?

Answer 1

by parts

Answer 2

(te^-t)
just and one to 1then put te over -t+1
te^-t+1/-t+1

Answer 3

\[t e ^{-1/}/-1 +\int\limits e^t dt\]

Answer 4

very carefully; you dont wana scare it

Answer 5

\[-t/e^t+ e^t +C\]

Answer 6

parts is good

..... e^-t
+t -e^-t
-1 e^-t
+0 ............. right?

Answer 7

-t e^-t + e^-t + C ??

Answer 8

so u=t? and dv=e^-t?

Answer 9

oh missed it :)

Answer 10

yes

Answer 11

so is v=-e^-t?

Answer 12

\[\int\limits_{}^{}te^{-t}dt=-te^{-t}+\int\limits_{}^{}e^{-t}dt=-te^{-t}-e^{-t}+C\]

Answer 13

u=t, du=1
dv=e^-t, v=-e^-t

Answer 14

Lets see if this reverts back...

Dt(-t e^-t + e^-t + C)

t e^-t - e^-t

e^-t (t-1) ... not quite, unless i forgot how to do that too ;)

Answer 15

thanks i got it :)

Answer 16

yay!!