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integral of 1/( e^(t+y) ) dy...?
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equal integral of e^-(t+y) = e^(-t-y)
u=(-t-y) du- -dy
=-1/(e^(t+y))
what would du be if u = -t-y..?
-1
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is it 1-dy..?
-dy
t is constant so its derivative is 0
oo gosh ofcourse..thanks you!
e^(t+y) = e^t * e^y hint
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and because e^t is a constant you can take it out of the integral and work with e^y
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