Question

in the boys & girls basketball lottery, participants buy a ticket with 4 different numbers from 0 to 9. each week a winner is determined by drawing 4 numbers from a hat containing the 10 one digit choices. any person who has a ticket white three of the four correct digits is a winner..
a) how many different tickets is it possible to buy?

b)how many winning possibilites are there each week?

c)if you buy one ticket whats your probabiltiy of winning?

Answer 1

a) 10 choose 4= (10!/(6!4!))=210
b) 1 ticket has all 4 correct, and 9 with 1 incorrect digit= 10 winners
c)10/210=1/21

Answer 2

i made a mistake by a factor of 2 on the last question i answered for you, i just corrected it.