Question

find the limit as x -->2 7/x-2

Answer 1

would it be 0/0 or undefined

Answer 2

equation is 7/x-2

Answer 3

you can also find the limit by derivating the numerator and denominator
the derivatives of 7 is 0
and the derivatives of x-2 is 1
therefore the limit would be 0/1 = 0

Answer 4

IF you're asking about
\[\lim_{x \rightarrow 2}{7 \over x-2}\], then you can notice that when substituting \(x=2\), we get a \(0\) at the denominator. Therefore, the limit is undefined and goes to \(\infty\) as x approaches \(2^+\) and \(-\infty\) as x approaches \(2^-\).

Answer 5

AnwarA has the correct approach. So in this case, L'Hopital's rule can't be used to evaluate the limit, as the third post states.