An angle whose supplement is 3 times the measure of it supplement
you dont have a complete sentence
\[180-\theta=3(180-\theta) \implies \theta=180 degrees\]
the english is screwy
i did what I understood ;)
well that is how the question is wrote out for me?
you got an absurd conclusion
no , write it again and double check
Find the measure of an angle whose supplement is 3 times the angle.
Thats the question
oops, the last word is complement, sorry its late
x + y = 180, y = 3x
\[180-\theta=3(90-\theta) \implies 2\theta=90 \implies \theta=45\]
3x + x = 180 x = 45
y = 135
\[if \ \theta>90\ then\ 180-\theta=3(\theta-90) \implies \theta=112.5\ else\ \theta=45\]
I'm not sure what ask but i think 2 way can solve frist: 180-x=3(90-x) or: 180=3(90-x) 180-x=270-3x 180=270-3x -x+3x=270-180 -270+180=-3x 2x = 90 -90 = -3x x= 90 -90/-3=x x=45 30 = x
@Nancy Lam: you are assuming that x<90. What if x>90?
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