Ask
your own question, for FREE!
Ask question now!
Mathematics
19 Online
OpenStudy (anonymous):
An angle whose supplement is 3 times the measure of it supplement
15 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
you dont have a complete sentence
15 years ago
OpenStudy (anonymous):
\[180-\theta=3(180-\theta) \implies \theta=180 degrees\]
15 years ago
OpenStudy (anonymous):
the english is screwy
15 years ago
OpenStudy (anonymous):
i did what I understood ;)
15 years ago
OpenStudy (anonymous):
well that is how the question is wrote out for me?
15 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
you got an absurd conclusion
15 years ago
OpenStudy (anonymous):
no , write it again and double check
15 years ago
OpenStudy (anonymous):
Find the measure of an angle whose supplement is 3 times the angle.
15 years ago
OpenStudy (anonymous):
Thats the question
15 years ago
OpenStudy (anonymous):
oops, the last word is complement, sorry its late
15 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
x + y = 180, y = 3x
15 years ago
OpenStudy (anonymous):
\[180-\theta=3(90-\theta) \implies 2\theta=90 \implies \theta=45\]
15 years ago
OpenStudy (anonymous):
3x + x = 180
x = 45
15 years ago
OpenStudy (anonymous):
y = 135
15 years ago
OpenStudy (anonymous):
\[if \ \theta>90\ then\ 180-\theta=3(\theta-90) \implies \theta=112.5\ else\ \theta=45\]
15 years ago
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I'm not sure what ask but i think 2 way can solve
frist:
180-x=3(90-x) or: 180=3(90-x)
180-x=270-3x 180=270-3x
-x+3x=270-180 -270+180=-3x
2x = 90 -90 = -3x
x= 90 -90/-3=x
x=45 30 = x
15 years ago
OpenStudy (anonymous):
@Nancy Lam: you are assuming that x<90. What if x>90?
15 years ago
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours! Join our real-time social learning platform and learn together with your friends!
Sign Up
Ask Question