find the area between the curves.
y=log x
y=x
x=1
x=10
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OpenStudy (amistre64):
yay!! an easy one :)
OpenStudy (amistre64):
let me draw a pic to see if we got the right interpretation
OpenStudy (amistre64):
OpenStudy (amistre64):
we integrate y=x between 1 and 10
then subtract y = log(x) between 1 and 10
OpenStudy (amistre64):
\[\int\limits_{1}^{10} (x - \log(x)). dx\]
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OpenStudy (amistre64):
x^2 x
---- - ----- from [1,10] right?
2 log(x)
OpenStudy (anonymous):
yes fro [1,10]
and thanks for the graph!
OpenStudy (amistre64):
x^2/2 = 100/2 - 1/2 = 99/2
99/2 - (10/log(10) - 1/log(1))
99/2 - (10 - 1/0).... lol; lookslike I forgot how to int my log
OpenStudy (anonymous):
thank you so much!
OpenStudy (amistre64):
libraries closing on me so good luck with this one :)
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OpenStudy (anonymous):
can you please help me with my other questiones i posted :(
OpenStudy (amistre64):
in about 10 minutes maybe; if they aint answered yet... gotta move to a new location :)
OpenStudy (anonymous):
okay i will wait thanks!
OpenStudy (amistre64):
log(x) = ln(x)/ln(10)
1/ln(10) is a constant so that gets put to the side for later
int(ln(x)) = x(ln(x) - 1)
xlnx - x
------- from 1,10
ln(10)
99/2 - [(10- 10/ln(10)) - (-1/ln(10))] is what i get