how do you solve 6x-10 over 7 divided by 9x-15 over 21?

Question

how do you solve 6x-10 over 7 divided by 9x-15  over 21?

anonymous · Answer

Well without it being equal to something you can't really 'solve' it...

anonymous · Answer

no there's a way to solve it because someone got the answer but i dont know what it is

amistre64 · Answer

it can be reduced, simplified; but not really solved; its always gonna have an x in it unless that x factors out

anonymous · Answer

so what would the answer be and how would you get that answer?

amistre64 · Answer

the other option is to plot the points on a graph that result from inputing values of x and the graph becomes the solution.... but without knowing tha tthis is a function with respect to x its rather redundant

anonymous · Answer

Is this the expression?
$$(6x-10) \div {{9x - 15} \over 21}$$

anonymous · Answer

no.. 6x - 10 is over 7, but everything else is right

anonymous · Answer

$${{6x-10} \over 7}\div {{9x - 15} \over 21}$$$$=2({{3x-5} \over 7}) \div 3({{3x-5} \over 7})$$$$={{2({{3x-5} \over 7})} \over {3({{3x-5} \over 7})}}$$$$ = {2 \over 3}$$

anonymous · Answer

Though you do need to stipulate that x cannot be equal to 5/3.

anonymous · Answer

one question.. how did you get both denominators 7?

anonymous · Answer

oh wait. I'm wrong.

anonymous · Answer

$${{6x-10} \over 7}\div {{9x - 15} \over 21}$$$$=2({{3x-5} \over 7}) \div {3 \over 3}({{3x-5} \over 7})$$$$={{2({{3x-5} \over 7})} \over {1({{3x-5} \over 7})}} = 2,\ \forall x \ne {5 \over 3} $$

anonymous · Answer

Forgot I factored a 3 from the top and bottom of the fraction on the right.

anonymous · Answer

thx .can you help me with another problem?

anonymous · Answer

maybe

anonymous · Answer

Heres the problem...8-y over y squared + 4 minus y - 2 over y squared + 4

anonymous · Answer

It would be very helpful if you would write these up in the equation editor because there are a number of ways to interpret what you wrote there.

anonymous · Answer

oh i didn't know you could do that. because I'm kind of new to this website .......
8-y/y squared + 4 minus  y-2/y squared + 4?   does that make a little more sense because I don't know how to do exponents so I just wrote it out

anonymous · Answer

$${{8-y} \over y^2+ 4} - {{y-2} \over y^2+ 4} $$

That?

anonymous · Answer

yah. how did u do that but anyway how do u solve it??

anonymous · Answer

Well they are over a common denominator already so just subtract the numerators.

anonymous · Answer

what answer would you get?