Question

compute the derivative y' of y=xsinxcosx

Answer 1

We can rewrite y as
\(y=\frac{1}{2}x\sin(2x)\)
Hence
\(y'=\frac{1}{2}\sin(2x)+x\cos(2x)\)

Answer 2

u did the product rule when taking the derivative?

Answer 3

yes

Answer 4

when u write xcos2x? can u explain why

Answer 5

\(y'=\frac{1}{2}\sin(2x)+\frac{1}{2}x\cdot 2\cos(2x)\)

Answer 6

ok./.... thank u very much