Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

how do i simplify a radical expression that has a variable in it?

OpenStudy (anonymous):

\[\sqrt[3]{x^7}\]

OpenStudy (amistre64):

make it a rational exponent :)

OpenStudy (anonymous):

\[x^{7/3}\]

OpenStudy (amistre64):

x^(7/3) = x^(6/3 + 1/3) x^2 cbrt(x)

OpenStudy (anonymous):

it needs to be simplified not solved

OpenStudy (amistre64):

that is simplified; in order to 'solve' we would have said x = some number

OpenStudy (amistre64):

to simplify just means to write it in another way

OpenStudy (amistre64):

cbrt(x^7) = x^2 cbrt(x)

OpenStudy (anonymous):

ok thanks but all the answers have either a 3 and an x or a 2 and a 3 and an x

OpenStudy (amistre64):

maybe it more accurate to write it like this: cbrt(x^7) <=> x^2 cbrt(x) :)

OpenStudy (amistre64):

\[\sqrt[3]{x^7} <=> x^2 \sqrt[3]{x}\]

OpenStudy (anonymous):

thank you so much

OpenStudy (amistre64):

yw :)

OpenStudy (anonymous):

\[\frac4{9-\sqrt6}\]

OpenStudy (anonymous):

rationalize the denimonator

OpenStudy (amistre64):

you gotta multiply by the conjugate; which is just cahngeing that - into a +

OpenStudy (amistre64):

4 (9+sqrt(6)) 4(9+sqrt(6)) ----------- = ----------- 81 -6 75

OpenStudy (amistre64):

multiply top AND bottom by the conjugate ;)

OpenStudy (anonymous):

thx

OpenStudy (amistre64):

yw :) if you post a new question in the question box, more people will get a chance to help and you wont run the risk of me not seeing it in this post :)

OpenStudy (anonymous):

\[\log_{5}75-\log_{5}3 \]

OpenStudy (anonymous):

write the expression as a single logarithm whose coefficient is 1?

OpenStudy (amistre64):

log(a) - log(b) = log(a/b) so, log5(75) - log(3) = log5(75/3) = log5(25)

OpenStudy (anonymous):

\[\sqrt{9x+22}=x \]

OpenStudy (amistre64):

^2 both sides to get: 9x +22 = x^2 0 = x^2 -9x +22 0 = (x-11)(x+2) x = 11 and -2 ; but we gotta dbl check because this way can have fake results: sqrt(9(11)+22) ?= 11 sqrt(99+22) ?= 11 sqrt(121) ?= 11 11 = 11 ; that ones good -------------------------------- sqrt(9(-2) +22) = -2 .... aint no way that one works lol x = 11 is the answer

OpenStudy (anonymous):

u r a math god!!

OpenStudy (amistre64):

more of a math demigod lol

OpenStudy (anonymous):

lol

OpenStudy (amistre64):

my indian name is "runs with scissors" ....

OpenStudy (anonymous):

\[\log_{9}25 \]

OpenStudy (anonymous):

calculator keeps giving me the wrong answer

OpenStudy (amistre64):

change of base it.... is my guess

OpenStudy (amistre64):

ln(25) ----- = answer ln(9)

OpenStudy (amistre64):

1.464.... maybe?

OpenStudy (anonymous):

thanks that worked

OpenStudy (amistre64):

it should :)

OpenStudy (amistre64):

spose we have 9^x = 25 log(9^x) = log(25) x log(9) = log(25) x = log(25)/log(9) x = log9(25) its all good

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!