Question

I have a question we are doing quadratic equation and I have an example which I do not think it can be an quadratic equation. x^5+3x-7=0

Answer 1

Because I believe if you factor the equation it becomes x^5-4

Answer 2

qudratic form : x^2 + x + C
x^5 is def not quadratic

Answer 3

so in other words you can't solve this equation?

Answer 4

This x^5-3x+7=0 is in standard form?

Answer 5

that is not in standard form for quadratic,

Answer 6

hey can u help me

Answer 7

suzi20 I have a question for you but if you would take 5^2+3x+7=0 this is a quadratic equation correct?

Answer 8

5^2+3x+7=0 yea this is quadratic

Answer 9

the answer would be x=-3+i \[\sqrt{131}/10\]

Answer 10

and -3-i sqrt 131/10

Answer 11

suzi20 is that correct what I just posted for the answer

Answer 12

sorry, i miss read, 5^2+3x+7=0 is not quadratic because 5^2 = 25 and this is constanta

Answer 13

3x + 32 = 0
x = -32/3

Answer 14

how would you create a quadratic equation that was not constata?

Answer 15

5x^+3x-7=0 would this be a quadratic equation since the last sign was changed to minus instead of addition

Answer 16

suzi20 or would it not make a difference would it still be constata?

Answer 17

5x^2 + 3x - 7 is quadratic since u have variables x^2 and x
5^2 + 3x - 7 is linear because u just have 1 variable which is x

Answer 18

then the answer would be x=-3+sqrt149/10, -3-sqrt149/10

Answer 19

5x^2 + 3x - 7
a = 5 b= 3 c=-7
D = b^2 - 4ac = 9 + 140 = 149
x = -b +/- sqrt (D) over 2a
= -3 +/- sqrt (149) over 10
x[1] = -3 + sqrt(149) over 10
x[2] = -3 - sqrt(149) over 10

Answer 20

Thank you suzi20 you was a big help!