how do you complete the square in the equation 4y^2-2x+8y+1=0?

Question

anonymous · Answer

Okay. I think I’ve got it. First off, move all your y’s to one side of the equation, and all your x’s to the other.

4y^2 + 8y = 2x – 1

Next step, you have to make 1 the coefficient of your y^2! So divide everything by 4.

y^2 + 2y = 2x/4 – ¼

Now, take the coefficient of your y^2 (which we made 1), and multiply it by the coefficient of y. That gives you 1. Insert this number on both sides of the equation!

y^2 + 2y + 1 = 2x/4 – ¼ + 1

Now you can make the left-hand side of the equation (y+1)^2!
All you have to do now is rearrange stuff in the formula, isolating the x.

2 (y + 1)^2 – 6/4 = x

I hope I haven’t made any mistakes!

anonymous · Answer

thanx a million!