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Mathematics 9 Online
OpenStudy (anonymous):

Factor completely: 6x^2-5y-3xy+10x

OpenStudy (anonymous):

\[(6x^2+10x)-(3xy+5y)=2x(3x+5)-y(3x+5)=(2x-y)(3x+5)\]

OpenStudy (anonymous):

(6x^2+10x)-(5y+3xy) 2x(3x+5)-y|(5+3x) so (2x-y)(5+3x)

OpenStudy (anonymous):

wait so why do you group together 6x squared + 10x and 5y + 3xy

OpenStudy (anonymous):

That's called factorization by grouping, and we did that because it would give a common factor in the end, as we saw.

OpenStudy (anonymous):

Ok I got it.

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