Ask
your own question, for FREE!
Mathematics
13 Online
Let P₃(R) be the vector space of polynomials over R of degree strictly less than 3. Let T: P₃ (R) →P₃ (R) be defined by T(⨍)= 2⨍’ (a) Show that T is a linear transformation (b) Find a basis for the kernel of T (c) Is T an isomorphism? Justify your answer.
Still Need Help?
Join the QuestionCove community and study together with friends!
\(T(f+g)=2(f+g)'=2(f'+g')=2f'+2g'=T(f)+T(g)\) \(T(\alpha f)=2(\alpha f)'=2\alpha f'=\alpha(2f')=\alpha T(f)\) Hence \(T\) is linear. \(f\in \ker T\iff T(f)=2f'=0\iff f'=0\iff f\equiv \text{costant}\) Obviously \(T\) is not an isomorphims since it is not injective ( because \(\ker T\neq 0\) )
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
VERNEISH:
Two objects are moving along separate linear paths where each path is described by position, d, and time, t.
Maci:
what are the best stock apps for people who want to start investing?
Twaylor:
genuienly how do i get better self control i keep watcing youtube and theres this
IzzyCookie:
|dw:1792074056138:dw| Uhm, I don't know where to ask this, but I'm in college welding at my community college, and I need help learning vertical welding for
thehearken:
not sure if this is considered spam, im sorry if it is, but does anyone have tips
10 hours ago
0 Replies
0 Medals
4 days ago
3 Replies
2 Medals
1 week ago
3 Replies
0 Medals
1 day ago
9 Replies
1 Medal
1 week ago
2 Replies
1 Medal