Mathematics
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OpenStudy (anonymous):
what is the limit as x approaches 0 when ((1-cosx)^2)/x
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OpenStudy (amistre64):
0 i think
OpenStudy (amistre64):
2(1-cosx) . sin(x) = 0
OpenStudy (anonymous):
Yes L'pthals
OpenStudy (amistre64):
yep :)
OpenStudy (amistre64):
otherwise you expand the top and see what you can do to it..
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OpenStudy (anonymous):
((1-cosx)(1-cosx))/x = 0?
OpenStudy (amistre64):
keep going....
OpenStudy (amistre64):
1 -2cos(X) + cos^2(x)
-------------------- ....
x
OpenStudy (anonymous):
doesn't (1-cosx)/x = o
OpenStudy (amistre64):
dunno; its been so long since I tried it the hard way :)
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OpenStudy (amistre64):
you could try squeeze this on a graph
OpenStudy (anonymous):
But, (1-cosx)/x times (1-cosx)/x = (1-cosx)^2 / x^2.......
OpenStudy (anonymous):
Why would you do that?
OpenStudy (amistre64):
i dunno why it cuts it short; but copy paste that link itno your address bar
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OpenStudy (anonymous):
@amogh - I'm just pointing out that I'm doing it wrong...
OpenStudy (amistre64):
OpenStudy (anonymous):
Yes, x will go with either of them, not both of them
OpenStudy (anonymous):
@amistre64: do you like ff4?
OpenStudy (anonymous):
Sh@t! I did the problem wrong on my test then.......
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OpenStudy (anonymous):
What did you answer?
OpenStudy (anonymous):
Thank you for the Wolfram alpha link amistre64. How much is that?
OpenStudy (anonymous):
I answered "0" but I didn't do my work correctly (analytically), so I get the problem wrong