Question

Would be the first derivative of this function with:

F(X)=(1+2x+x^3)^1/4 ?

Answer 1

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Answer 2

\[f(x) = (1 + 2*x + x^3)^{1/4}\]

Answer 3

OK. \[f'(x) = (1/4)(1+2*x+x^3)^{-3/4} * ( 1 + 2 + 3x^2 )\]

Answer 4

the general concept is: g(f(x))'=g'(f(x)).f'(x)

Answer 5

oh, ok, I see. thanks

Answer 6

f'(x)=[(1/4)(1+2∗x+x3)^−3/4].(2+3x^2)