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OpenStudy (anonymous):
Let f(x)=-4x-2 and g(x)=5x-6. find F(little black circle ) g and state it's domain
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OpenStudy (anonymous):
they all are real numbers
but is 6 or 1
OpenStudy (anonymous):
no domain is all real numbers.
\[f(g(x))=f(5x-6)=-4(5x-6)-2\]
OpenStudy (anonymous):
now we can multiply and combine like terms
\[f(g(x))=-4(5x-6)-2=-20x+24-2=-20x+22\]
OpenStudy (anonymous):
-20x
OpenStudy (anonymous):
this is a line, so domain all real numbers.
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OpenStudy (anonymous):
20
OpenStudy (anonymous):
\[-20x+20\]
OpenStudy (anonymous):
34 or 12 are in the answer somewhere
OpenStudy (anonymous):
or 14
OpenStudy (anonymous):
no i don't see 34 or 14 anywhere in \[f(g(x))\]
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OpenStudy (anonymous):
possible answers
..-20x^2+14x+12 all real except
..8x^2+34x-30 all real except 1
...8x^2+34-30 all real
...-20x^2+14x+12 all real
OpenStudy (anonymous):
OOOOOOhhhhhhhhhhhhhhhhh
OpenStudy (anonymous):
\[fg(x) not f(g(x))\]
OpenStudy (anonymous):
f o g
OpenStudy (anonymous):
-20x^2+14x+12 all real except 6
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OpenStudy (anonymous):
well if that is it, i am right. if it is f times g then one of those is the answer. but that open circle does not mean mulitply
OpenStudy (anonymous):
no it would not be all real except 6 because it is a polynomial so it would be all real numbers.
OpenStudy (anonymous):
no it is a close circle
OpenStudy (anonymous):
\[-20x^2+6x+8\]
OpenStudy (anonymous):
nope you are right sorry
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OpenStudy (anonymous):
no you are right
OpenStudy (anonymous):
\[-20x^2+12x+12\]
OpenStudy (anonymous):
okay yeay
OpenStudy (anonymous):
domain all real numbers
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