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Mathematics 18 Online
OpenStudy (anonymous):

Management. Six candidates for manager of a department store are ranked according to the weighted average of several criteria. How many different rankings are possible for the top four candidates if no two candidates receive the same rank?

OpenStudy (anonymous):

It's not completely clear to me what you're asking. So they are ranked 1 through 6 I'm geussing. Are you saying that the top 4 are selected, and then we want to find how many different ways we can rank those preselected top 4?

OpenStudy (anonymous):

nope thats what the question reads

OpenStudy (anonymous):

A) 1296 B) 30 C) 24 D) 360 E) 36

OpenStudy (anonymous):

well if you want the different arrangements of the top 4 and they are preselected, you would have the permutations on 4 objects which is 4!=4*3*2*1=24

OpenStudy (anonymous):

what throws me off is the 6

OpenStudy (anonymous):

yeah it's strangely worded

OpenStudy (anonymous):

If they mean there are 6 rankings and you pick 4 people and want to know the possibilities of ranking for them it is 6*5*4*3=360. I geuss you have to interpret the question

OpenStudy (anonymous):

you think it can be a combination C(6,4)?

OpenStudy (anonymous):

that gives the number of groups of 4 you could pick.

OpenStudy (anonymous):

I dont think that's what it is asking

OpenStudy (anonymous):

answer is not even on their if it was

OpenStudy (anonymous):

I would geuss they wanted the 6*5*4*3, but they said how many possibilities for the top 4, which to me means youre only permuting 1st 2nd 3rd 4th place which is 24

OpenStudy (anonymous):

you get to pick what you think it means i geuss

OpenStudy (anonymous):

yea... ima go with 24

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