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Mathematics 30 Online
OpenStudy (anonymous):

T=5((x−2)/4)+1

OpenStudy (anonymous):

and solve for what?

OpenStudy (anonymous):

x

OpenStudy (anonymous):

sorry

OpenStudy (anonymous):

steps please.

OpenStudy (anonymous):

I answered that.

OpenStudy (anonymous):

i still dont understand it though

OpenStudy (anonymous):

Do you know why you can equate two sides of an equation?

OpenStudy (anonymous):

\[x=\frac{2}{5} (3+2 T) \]

OpenStudy (anonymous):

i know about the order of operations thats not what I need to know.

OpenStudy (anonymous):

i need all steps from beginning please!

OpenStudy (anonymous):

Robtobey how did you get your solution?

OpenStudy (anonymous):

there is no 10 in the equation...

OpenStudy (anonymous):

*facepalm*

OpenStudy (anonymous):

jwaddell your equation is little confusing. if solve for x. then x would equal some number with T in them.

OpenStudy (anonymous):

yes i know

OpenStudy (anonymous):

if you solve it that way then. \[x=(4(\frac{T}{5})-1)+2\]

OpenStudy (anonymous):

WOW the T is throwing me off

OpenStudy (anonymous):

first, distribute 5 to (x-2)/2 sop, we get (5x-10)/4 + 1=0, if T=0 then, the LCD is 4, so it will become (5x-10+4)/4=0 5x-6=0 5x=6 x=1.2

OpenStudy (anonymous):

if T=0 then x=1.1999999999

OpenStudy (anonymous):

or, if the value of T is not given, then, x=(4T+6)/5

OpenStudy (anonymous):

Pat yours makes sense thanks!

OpenStudy (anonymous):

you are welcome.

OpenStudy (anonymous):

thanks for the medal.

OpenStudy (anonymous):

no prob you wanna help me with one more?

OpenStudy (anonymous):

sure.

OpenStudy (anonymous):

\[A= (3m+2)/(m-1)\]

OpenStudy (anonymous):

solve for m

OpenStudy (anonymous):

m=(A(m-1)-2)/3

OpenStudy (anonymous):

that is not right pat. since the other m is there also.

OpenStudy (anonymous):

yeah, i had a mistake, i did not see it. thanks

OpenStudy (anonymous):

m=(A+2)/(A-3) what did you get?

OpenStudy (anonymous):

can u show me the steps too please

OpenStudy (anonymous):

m=(-2-A)/3-A

OpenStudy (anonymous):

(3m+2)/(m-1)=A, then cross multiply, you will get 3m+2=Am-A 3m-Am=-2-A m(3-A)=-2-A m=(-2-A)/(3-A)

OpenStudy (anonymous):

would't it be Am-3m=2-A???

OpenStudy (anonymous):

or actually Am-3m-2+A

OpenStudy (anonymous):

jwaddell06, Do you still want to see how the first problem was solved, now that the dust has settled?

OpenStudy (anonymous):

\[T=\frac{5 (x-2)}{4}+1 \]\[T-1=\frac{5 (x-2)}{4} \]\[4(T-1)=5 (x-2)\]\[\frac{4(T-1)}{5}=(x-2)\]\[\frac{4(T-1)}{5}+2=x \]Simplify the left side to obtain:\[\frac{2}{5} (2 T+3)=x \]

OpenStudy (anonymous):

now why wouldnt you multiply the 5 into x-2

OpenStudy (anonymous):

The object is to isolate x on the right hand equation side. The easiest path for me was to divide by 5 leaving x - 2. When +2 is added to each side, x is left alone.

OpenStudy (anonymous):

That makes sense a little but i thought whenever you were given something like 5(x-2) you were supposed to make it 5x-10 then isolate x from there.

OpenStudy (anonymous):

Well the final result should be OK. Give me a minute to work it out.

OpenStudy (anonymous):

\[4(T-1)=5 (x-2) \]\[4(T-1)=5 x-10 \]\[4(T-1)+10=5 x \]\[\frac{4(T-1)+10}{5}=x \]\[\frac{2}{5} (2 T+3)=x \]

OpenStudy (anonymous):

ok i get it up to the last part how do you get 2/5(2T+3)

OpenStudy (anonymous):

\[\frac{4(T-1)+10}{5} \]Simplify the numerator\[\frac{(4 T+6)}{5}\]Factor the numerator\[\frac{(2 (2 T+3))}{5}=x \]Factor the expresssion\[\frac{2}{5} (2 T+3) \] I actually use Mathematica to do the calculations and had to resolve the problem by hand to answer you follow up questions.

OpenStudy (anonymous):

what is mathematica??

OpenStudy (anonymous):

I have to break off for about 10 minutes. Will be back then to answer any other questions.

OpenStudy (anonymous):

i dont understand how to simplify the numerator like that. sorry its been 10 years since I did algebra if not longer.

OpenStudy (anonymous):

what is mathematica?? Here is an introductory video. http://www.wolfram.com/solutions/education/students/

OpenStudy (anonymous):

Simplification is a nicety, but not required to present a valid problem solution.

OpenStudy (anonymous):

You're still looking at this .-.

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