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integrate e^(sqrt x )
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The integral in this case is \[\frac{1}{a'}* e^a\]
where a' is the derivative of a
Let t = sqrt(x) So dx = 2.t.dt Integrate 2 . e^t . t . dt u = 2t dv = e^t dt -> du = 2dt v = e^t -> integral(2e^t t dt) = 2 t e^t - integral(2 e^t dt) = 2 t e^t - 2 e^t = e^t (t-1) . 2 , t = sqrt_x as above *
thanks
by parts yes? \[\int e^{\sqrt{x}}dx=2(\sqrt{x}-1)e^{\sqrt{x}}\]
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