Use identities (no calculators) to find the exact value for (sin 9)(sin 36)-(cos 9)(cos 36)
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OpenStudy (anonymous):
9+36 =?
OpenStudy (anonymous):
how can you play with those angles to get an angle for which there is an exact value
OpenStudy (anonymous):
does this equals cos 45?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
which is 1/ sqrt(2)
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OpenStudy (anonymous):
\[\sin \theta = \cos 90 - \theta\]
OpenStudy (anonymous):
How do I figure out if its positive of negative
OpenStudy (anonymous):
sines, cosines and tangents in the first quadrant (0-90 degrees) are all positive
OpenStudy (anonymous):
i've just checked my maths formula book and the given expression = -cos(9 + 36) not
cos (9+36) so the correct answer is -(1/sqrt2)
OpenStudy (anonymous):
this is not the formula for \[cos(a+b)\] but it is its negative.
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OpenStudy (anonymous):
of course 9+36=36+9=45
OpenStudy (anonymous):
but the formula for
\[cos(a+b)=cos(a)cos(b)-sin(a)sin(b)\]
OpenStudy (anonymous):
and \[sin(a)sin(b)-cos(a)cos(b)=-(cos(a)cos(b)-sin(a)sin(b)\] that is why you had to change the sign from
\[\frac{\sqrt{2}}{2}\]to
\[-\frac{\sqrt{2}}{2}\]