Question

Running 4/3 of his usual speed, A person improves his timing by 10 minutes. Find his usual time to cover the distance.

Answer 1

s = d/t

Answer 2

(4/3)Ns = d/(Nt-10)

Answer 3

Ns = d/(Nt)

Answer 4

(4/3)Ns = d/(Nt-10)

Ns = d/(Nt)

(4/3)d/(Nt) = d/(Nt-10)

Answer 5

cross multiply

(4/3)d(Nt-10) = d(Nt)

d(Nt(4) - 40)
----------- = d(Nt) ; /d and *3
3

Nt(4) - 40 = Nt(3)

Nt(4-3) = 40

Answer 6

his Normalt time is 40 minutes

Answer 7

..... maybe lol

Answer 8

yes.......
since time is inversely propotional to speed
let his earlier time be x min
so current time=3x/4 min
=>x- (3x/4)= 10
=>x=40