Mathematics
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OpenStudy (anonymous):
m^2 + 2m - 3/m^2 +4m -5 x m^2 - 3m - 10/m^2 + 5m + 6 i got -3m/10m
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OpenStudy (anonymous):
m^2 + 2m - 3/m^2 +4m -5 times m^2 - 3m - 10/m^2 + 5m + 6 i got -3m/10m
OpenStudy (anonymous):
no i don't think that is correct
OpenStudy (anonymous):
neither do i :p
OpenStudy (anonymous):
after factoring numerator is \[(m-1)(m+3)(m-5)(m+2)\]
OpenStudy (anonymous):
denominator is
\[(m+5)(m-1)(m+3)(m+2)\]
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OpenStudy (anonymous):
oh i didnt factor :|
OpenStudy (anonymous):
gotta factor and cancel.
OpenStudy (anonymous):
common factor are m-1, m+3, m+2
OpenStudy (anonymous):
can you help me with one more?
OpenStudy (anonymous):
10-5x/3 divided by x-2/12x
short one
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OpenStudy (anonymous):
leaving \[\frac{m-5}{m+5}\]
OpenStudy (anonymous):
\[\frac{10-5x}{3}\div\frac{x-2}{12x}\]?
OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
just like with regular fraction invert and multiply
OpenStudy (anonymous):
i got 120x-60x^2/3x-6
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OpenStudy (anonymous):
\[\frac{10-5x}{3}\times \frac{12x}{x-2}\]
OpenStudy (anonymous):
cancel first, multiply last
OpenStudy (anonymous):
what do i cancel out?
OpenStudy (anonymous):
\[\frac{5(x-2)\times 12x}{3(x-2)}\]
OpenStudy (anonymous):
cancel the 3 and the x - 2
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OpenStudy (anonymous):
leaving you with
\[5\times 4x=20x\]
OpenStudy (anonymous):
oopsssssssssss
OpenStudy (anonymous):
wrong sorry
OpenStudy (anonymous):
sorry give me a second i factored incorrectly
OpenStudy (anonymous):
cancel the x-2 not the 3
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OpenStudy (anonymous):
hold on
OpenStudy (anonymous):
\[\frac{10-5x}{3}\times \frac{12x}{x-2}=\frac{5(2-x)\times 12x}{3(x-2)}\]
OpenStudy (anonymous):
i factored incorrectly at first. sorry.
OpenStudy (anonymous):
now 3 goes in to 12 4 times so you can cancel the 3 and replace the 12 by a 4
OpenStudy (anonymous):
yea i saw that but i didnt know cus ur the one with the ansers :p
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OpenStudy (anonymous):
and finally \[\frac{2-x}{x-2}=-1\]
OpenStudy (anonymous):
hope that is clear
OpenStudy (anonymous):
so you can cancel the 2-x and the x-2 but make sure to change the sign, because it is -1 and not 1
OpenStudy (anonymous):
whered the 5 go?
OpenStudy (anonymous):
still up there. so you get
\[-20x\]
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OpenStudy (anonymous):
ohk thanks
OpenStudy (anonymous):
\[5\times 5x\times -1=-20x\]
OpenStudy (anonymous):
typo
OpenStudy (anonymous):
\[5\times 4x\times -1=-20x\]
OpenStudy (anonymous):
so its -20x/x-2?
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OpenStudy (anonymous):
nope
OpenStudy (anonymous):
x-2 in denominator canceled with 2-x in numerator to give -1
OpenStudy (anonymous):
so there is no denominator at all.
OpenStudy (anonymous):
just -20x
OpenStudy (anonymous):
oh.
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OpenStudy (anonymous):
okay thank you
OpenStudy (anonymous):
is it clear that \[\frac{2-x}{x-2}=-1\]?
OpenStudy (anonymous):
i dont see why it turned into -1
OpenStudy (anonymous):
the top is the negative of the bottom
OpenStudy (anonymous):
try it with numbers:\[\frac{2-5}{5-2}=-1\]
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OpenStudy (anonymous):
ah. i get it now
OpenStudy (anonymous):
\[\frac{2-10}{10-2}=-1\]
OpenStudy (anonymous):
-3/3 = -1
OpenStudy (anonymous):
-8/8=-1
OpenStudy (anonymous):
a good trick to know\[\frac{a-b}{b-a}=-1\]
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OpenStudy (anonymous):
ok well im gettin off now thank you
OpenStudy (anonymous):
yes the top is the negative of the bottom that is why you can cancel
OpenStudy (anonymous):
welcome