A plane landing at PDX has to descend 1650ft over a diagonal distance of 9700ft. What is the angle of depression of the plane?
help would be nicce

Question

A plane landing at PDX has to descend 1650ft over a diagonal distance of 9700ft. What is the angle of depression of the plane?
help would be nicce<33

anonymous · Answer

$$\frac{\text{ArcSin}[1650/9711]}{\pi }180 = 9.78261 \text{ Degrees} $$

anonymous · Answer

oh gotcha thanks!

anonymous · Answer

Sorry.  Entered 9711 and it should have been 9700.  Not much difference in the angle.
$$\frac{\text{ArcSin}[1650/9700]}{\pi }180 = 9.79381 \text{ degrees} $$

anonymous · Answer

Thank you for the medal.

anonymous · Answer

no prob<3

anonymous · Answer

myininaya,

Here's what I got:
$$\text{Cos}\left[\text{ArcSec}\left[\frac{5}{4}\right]+\text{ArcSin}\left[\frac{1}{3}\right]\right]=-\frac{1}{5}+\frac{8 \sqrt{2}}{15}$$