Question

A plane landing at PDX has to descend 1650ft over a diagonal distance of 9700ft. What is the angle of depression of the plane?
help would be nicce<33

Answer 1

\[\frac{\text{ArcSin}[1650/9711]}{\pi }180 = 9.78261 \text{ Degrees} \]

Answer 2

oh gotcha thanks!

Answer 3

Sorry. Entered 9711 and it should have been 9700. Not much difference in the angle.
\[\frac{\text{ArcSin}[1650/9700]}{\pi }180 = 9.79381 \text{ degrees} \]

Answer 4

Thank you for the medal.

Answer 5

no prob<3

Answer 6

myininaya,

Here's what I got:
\[\text{Cos}\left[\text{ArcSec}\left[\frac{5}{4}\right]+\text{ArcSin}\left[\frac{1}{3}\right]\right]=-\frac{1}{5}+\frac{8 \sqrt{2}}{15}\]