Question

Am I doing this problem right? 6^((log_36)^4)=16

Answer 1

6^((log_36)^4)=6 ^ ( log

Answer 2

what base log is that?

Answer 3

6^((log_36)^4)=6 ^ ( (log 6^2 )^4 = 2^4 = 16

Answer 4

Thats what I did, but when I put it into my hmwk (online) then it was wrong...?

Answer 5

one sec

Answer 6

6^((log_36)^4) = 6 ^ [ (log_6 6^2) ^4 ] = 6 ^ [ 2^4] = 6^16

Answer 7

Oh, so I cancelled too many 6's?

Answer 8

dunno, did my solution make sense?

Answer 9

2 821 109 907 456

Answer 10

um, it did but I'm confused still.
It doesn't match very well with what I'm getting, well it is but it's not pretty.

Answer 11

but thats the right answer, correct ?

Answer 12

6^16=2.821109907e^12 , not sure gonna try

Answer 13

not right

Answer 14

no dont approximate

Answer 15

2 821 109 907 456

Answer 16

why no decimal

Answer 17

theres no need for it

Answer 18

what base is the log?

Answer 19

went to the end, and it showed me the answer is 2

Answer 20

yeah, you probably should give us the whole question

Answer 21

I did

Answer 22

it says to simplify that equation i gave

Answer 23

what base is the log?

Answer 24

I'm confused about that to, i think its 6

Answer 25

\[6^{\log _{36^{4}}} = .....
.\log _{6^{x}}=\log6^{2\times4}......x=8..........6^{8}\]
?

Answer 26

no, I dont think the 4 is a power of 36

Answer 27

at the bottom eqution can u try rewrite

Answer 28

It's ok, I moved on from that question so you dont need to waste your brain power on this question. Thanks for trying :)

Answer 29

\[6^{\log _{36}4}\]

Answer 30

ahh base is 36 and 4 is not an exponent
x = log base 36 (4) => 36^x = 4 => 6^2x = 4
thus x = log base 6 (4) /2
6^x = sqrt(4) = 2

Answer 31

I didn't understand that other answer, but it went away before i could finish looking. I understand yours a little better.

Answer 32

\[36=6^{2}\]\[36^{x}=4\]\[6^{2(x)}=4\]\[2x=4\]\[x=\frac{4}{2}\]\[x=2\]