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what the derivative of 2arctan(2x) ?
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\[2( \frac{1}{1+4x^2})*2\]
4[1/(1+4x^2)]
can you explain a little better how you got that?
\[{d \over dx }\tan ^{-1}x=/1+x^2\]
apply this formula for 2arctan(2x)
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instead of x, here we have 2x, so by chain rule next we multiply with the derivative of 2x, that is 2
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yes how did you get 4x^2?
since instead of x,we have 2x.so (2x)^2=4x^2
ok?
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ahhh gotcha...
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