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Mathematics 18 Online
OpenStudy (anonymous):

what the derivative of 2arctan(2x) ?

OpenStudy (anonymous):

\[2( \frac{1}{1+4x^2})*2\]

OpenStudy (anonymous):

4[1/(1+4x^2)]

OpenStudy (anonymous):

can you explain a little better how you got that?

OpenStudy (anonymous):

\[{d \over dx }\tan ^{-1}x=/1+x^2\]

OpenStudy (anonymous):

apply this formula for 2arctan(2x)

OpenStudy (anonymous):

instead of x, here we have 2x, so by chain rule next we multiply with the derivative of 2x, that is 2

OpenStudy (anonymous):

is it helpful?

OpenStudy (anonymous):

yes how did you get 4x^2?

OpenStudy (anonymous):

since instead of x,we have 2x.so (2x)^2=4x^2

OpenStudy (anonymous):

ok?

OpenStudy (anonymous):

ahhh gotcha...

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