The hypotenuse of a right triangle is 15ft long. One leg is 3ft shorter than the other. Find the lengths of the legs. Please someone help me work through this
l^2 + (l-3)^2 = 15^2
15^2=x^2+(x-3)^2
15^2=x^2+x^2-6x+9 15^2=2x^2-6x+9
how do i do this amistre64
well ..... we use the pythag thrm which states: hyp^2 = leg^2 + other leg^2 15^2 = l^2 + (l-3)^2 from the problem stated agree?
i got x=-9 x=-12 so since there r no - then answer should be 9, 12 right
yes
225 = l^2 + l^2 -6l +9 ; go for broke... 0 = 2l^2 -6l - 216 agree?
yes
factor out the common 2 0 = l^2 -3l -108 ; solve for zeros
what is your favorite way to get the zeros of this quadratic?
?
how do we factor this quadratic?
we can complete the square if you like
or we can use the quadratic formula..
we can use 0=x^2-31x-108
divide both sides by 31
x=3,-3 no - x=3 x=3?
let me clean this up for you; l looks like '1' but its a letter L 0 = x^2 -3x -108 ; try that :)
divide both sides by 3
x=36 x=33
or is it still 12, 9
108+_____ = x^2 -3x +_____ ; complete the square 108 +9/4 = (x-(3/2))^2 ; sqrt side +- sqrt(441/4) = x-(3/2) ; +3/2 x = 3/2 +- 21/2
x = 24/2 = 12 or x = -18/2 = -9; lets assume its |-9| = 9 try them out does: 15^2 = 12^2 + 9^2 ??
225=144=81 YES
then we found our answers :) You just have to be more efficient at the quads ... and that takes alot of practice ;)
ok so the answers are 12, 9
yes
if leg = 12; the other leg = (12-3) = 9
ty so much
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