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Find the diagonal of a cube if its side equals 5.
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\[=\sqrt{5^{2}+ (5\sqrt{2})^{2}}=\sqrt{125}=5\sqrt{5}\]
i think you're wrong dumbcow :) ?( if a side is 5 on the square, then you can use a² + b² = c² which would be 5² + 5² = 50 or sqrt(50) is your answer... because squares' internal angles are made of 90 degrees each... so you can use that Pythagorean formula
@paul you are correct for finding diagonal for square sqrt(50) = 5sqrt(2) diagonal of cube is from corner to corner this triangle has legs of 5 and 5sqrt(2)
oh yeah... question said cube... sorry
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